120ft of fencing whats the maximum area enclosed

Enclosing three sides of a fence huh? | Yahoo Answers

Area of a rectangle = Length * Width. We know that the total perimeter has to be 120 feet because thats all the fencing we have. 120 = 2L + W. Now get one variable by it's self W would be easiest. W = 120 - 2L. Place this into the formula for area. Area = Length * Width. Area = L * (120 - 2L) Area = 120L - 2L^2【Get Price】

Find Maximum Area Enclosed by a Fence - YouTube

Find the maximum area is a common application in Algebra. Learn how to find the maximum area a rectangular fence can enclose.【Get Price】

If 800 feet of fencing is available find the maximum area ...

If 800 feet of fencing is available find the maximum area that can be enclosed. Perimeter of a rectangle is: 2l + 2w = P However we're given one side (length) is bordered by the river and the fence length is 800 so we have: So we have l + 2w = 800 Rearranging in terms of l we have: l = 800 - 2w The Area of a rectangle is: A = lw【Get Price】

A farmer has 120 feet of fencing to enclose a rectangular ...

A farmer has 120 feet of fencing to enclose a rectangular plot for some of his animals. One side of the area borders on a barn. a.) If the farmer does not fence the side along the barn find the length and width of the plot that will maximize the area? b.) What is the maximum area that can be enclosed? _____【Get Price】

SOLUTION: A rectangle has 200 feet of fencing with which to ...

A rectangle has 200 feet of fencing with which to enclose two adjacent rectangle corrals. What dimensions should be used so the enclosed area will be a maximum? what is the maximum area? Draw the picture of 2 adjacent rectangles.【Get Price】

Maximum Area For Three Side Fence Q13 - YouTube

Try to do this problem using alternate method.【Get Price】

SOLVED:You have 120 feet of fencing to enclose a

So I know that that maximum is going to take place. Our maximum area is going to take place when w is 30 and if w is 30 I could go back up here and the length would have to be 120 minus twice 30 which is 60. So when the length is 60 and if I just do it fast double check 30 plus the 60 would be 90 plus. The 30 would end up being 120 ft.【Get Price】

Fencing Near - Affordable Fences

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Grade 10 Quadratics Problem? | Yahoo Answers

A rectangular field is to be enclosed by 400m of fence. what is the maximum area? wut i got so far: let x= length (m) let y= width (m) perimeter= 2 width + 2 length 400= 2x+2y 2x= 400-2y 400= (400 - 2y) +2y 0= (400 - 2y)( 2y - 400) y= 200 x= 400 - y x= 400 - 200 x= 200 here's the problem It can't be right because the max perimeter is 400 and i need 4 sides if: y=200 original equation: 400= 2 ...【Get Price】